Injection Molding Machine Selection Quizzes

What is the required clamping force for a product with a projected area of 12000 mm² and an injection pressure of 60 MPa, with a safety factor of 1.4?

The correct clamping force is calculated using F = p × A × S = 60 MPa × 12000 mm² × 1.4 = 1,008,000 N (approx. 101t). The formula considers injection pressure, projected area, and safety factor.

If a product weighs 150g and the density of the material is 1.5g/cm³, what should be the minimum actual injection volume of the injection molding machine?

The product's volume is calculated as 150g / 1.5g/cm³ = 100 cm³. Thus, the actual injection volume should be greater than 100 cm³ to accommodate this product size.

Which parameter influences the selection of an injection molding machine for heavy products?

Heavier products may require higher injection pressures to ensure complete mold filling. Injection pressure is crucial for avoiding defects like short shots in thick-walled products.

What is the primary factor to consider when selecting the tonnage of an injection molding machine?

The tonnage of an injection molding machine is primarily determined by the projected area of the product on the parting surface. This is because the clamping force needed to keep the mold closed during injection depends on this area, as described by the formula \(F = p \times A \times S\). Other factors like color, brand, or mold material are not directly related to tonnage selection.

How is the required clamping force for an injection molding machine calculated?

The required clamping force is calculated using the formula \(F = p \times A \times S\), where \(p\) is the injection pressure, \(A\) is the projected area, and \(S\) is the safety coefficient. This ensures the mold is held together during injection.

What influences the choice of injection molding machine in terms of product weight?

Product weight influences the selection of an injection molding machine by determining the necessary injection volume. The theoretical injection volume is calculated based on screw diameter and stroke, while actual volume needs consideration for efficient production.

Why might a heavier product require a higher injection pressure?

Heavier products may need higher injection pressures to ensure that the plastic melt fills the mold cavity completely, preventing defects like short shots. This affects machine choice as different machines provide varying pressures.

How is the clamping force for an injection molding machine determined?

The required clamping force is calculated by considering the projected area of the product on the mold's parting surface, injection pressure, and a safety coefficient. This ensures that the mold stays closed during injection. Product weight or open stroke are not direct factors in this calculation.

What determines the required injection volume for an injection molding machine?

The required injection volume is determined by converting the product's weight into volume using the material's density. This ensures that the machine can inject enough material to fill the mold cavity properly. Mold size and projected area are not direct determinants of injection volume.

Why might a higher injection pressure be necessary for heavier products?

Heavier products may require higher injection pressures to ensure the plastic melt fills the entire mold cavity without leaving defects such as short shots. This is crucial for achieving uniform distribution of material within the mold, especially for thick-walled items.

What is the formula to calculate the required clamping force in an injection molding machine?

The correct formula to determine the required clamping force is F = p × A × S. Here, 'p' represents the injection pressure, 'A' is the projected area on the mold parting surface, and 'S' is the safety coefficient. This formula ensures the mold stays closed during injection.